Equazioni bilanciate il giorno precedente |
K2Cr2O7 + 2 CH3CH3CHOHCH3 + 4 H2SO4 = Cr2(SO4)3 + K2SO4 + 2 CH3CH3CH3COOH + 5 H2O
CH3CH2CH2OH + O2 = CO2 + H2O =>
2 CH3CH2CH2OH + 9 O2 = 6 CO2 + 8 H2O
KO2 + CO2 + HO2 = KHCO3 + O2 =>
2 KO2 + 2 CO2 + 2 HO2 = 2 KHCO3 + 3 O2
ZnSO4*7H2O + CaCl2*2H2O = CaSO4 + ZnCl2 + H2O =>
ZnSO4*7H2O + CaCl2*2H2O = CaSO4 + ZnCl2 + 9 H2O
Na(CO3) + HCl = NaCl + H(CO3) =>
Na(CO3) + HCl = NaCl + H(CO3)
Ni(HCO3)2 = Ni2(CO3)2 + CO2 + H2O =>
2 Ni(HCO3)2 = Ni2(CO3)2 + 2 CO2 + 2 H2O
KO2 + CO2 + HO2 = KHCO3 + O2 =>
2 KO2 + 2 CO2 + 2 HO2 = 2 KHCO3 + 3 O2
Ni(HCO3)2 = Ni2(CO3)2 + CO2 + H2O =>
2 Ni(HCO3)2 = Ni2(CO3)2 + 2 CO2 + 2 H2O
F + PbCl4 = FCl + Pb =>
4 F + PbCl4 = 4 FCl + Pb
K2Cr2O7 + CH3CH3CHOHCH3 + H2SO4 = Cr2(SO4)3 + K2SO4 + CH3CH3CH3COOH + H2O =>
K2Cr2O7 + 2 CH3CH3CHOHCH3 + 4 H2SO4 = Cr2(SO4)3 + K2SO4 + 2 CH3CH3CH3COOH + 5 H2O
Na(CO3) + HCl = NaCl + H(CO3) =>
Na(CO3) + HCl = NaCl + H(CO3)
(NH4)NO3 + Pb(NO3)2 = NH4(NO3)2 + PbNO3 =>
(NH4)NO3 + Pb(NO3)2 = NH4(NO3)2 + PbNO3
CH3CH2OK + CH3Cl = CH3CH2Cl + CH3OK =>
CH3CH2OK + CH3Cl = CH3CH2Cl + CH3OK
AlCl3 + Na2C2O4 = Al2(C2O4)3 + NaCl =>
2 AlCl3 + 3 Na2C2O4 = Al2(C2O4)3 + 6 NaCl
SnCl2 + HgCl = Hg + SnCl4 =>
SnCl2 + 2 HgCl = 2 Hg + SnCl4
CuCl2*2H2O + Fe + HCl = Cu + FeCl3 + H3O =>
3 CuCl2*2H2O + 4 Fe + 6 HCl = 3 Cu + 4 FeCl3 + 6 H3O
NH3 + H2(SeO4) = NH4 + SeO4 =>
2 NH3 + H2(SeO4) = 2 NH4 + SeO4
Al + Hg(CH3COO)2 = Al(CH3COO)3 + Hg =>
2 Al + 3 Hg(CH3COO)2 = 2 Al(CH3COO)3 + 3 Hg
Al + Hg(CH3COO)2 = Hg + Al(CH3COO) =>
2 Al + Hg(CH3COO)2 = Hg + 2 Al(CH3COO)
CuNO3 = Cu + N + O3 =>
CuNO3 = Cu + N + O3
SrO + N2O5 = Sr(NO3)2 =>
SrO + N2O5 = Sr(NO3)2
HBr + NaOH = NaBr + H + O =>
HBr + NaOH = NaBr + 2 H + O
KO2 + CO2 + HO2 = KHCO3 + O2 =>
2 KO2 + 2 CO2 + 2 HO2 = 2 KHCO3 + 3 O2
XeOF4 + O2 = XeO3 + F =>
XeOF4 + O2 = XeO3 + 4 F
NaH + H2SO4 = Na2SO4 + H3 =>
6 NaH + 3 H2SO4 = 3 Na2SO4 + 4 H3
Cr(OH)3 + H2SeO4 = Cr(HSeO4)3 + H2O =>
Cr(OH)3 + 3 H2SeO4 = Cr(HSeO4)3 + 3 H2O
Pb2(NO3)4 + K2CO3 = PbCO3 + KNO3 =>
Pb2(NO3)4 + 2 K2CO3 = 2 PbCO3 + 4 KNO3
P4 + N2 = P3N5 =>
3 P4 + 10 N2 = 4 P3N5
Cr2S3 + KNO3 = K2CrO4 + NO + K2SO4 =>
Cr2S3 + 10 KNO3 = 2 K2CrO4 + 10 NO + 3 K2SO4
Ca(ClO)2 + HOH = Ca(OH)2 + HClO =>
Ca(ClO)2 + 2 HOH = Ca(OH)2 + 2 HClO
NO3Ag + H2O + PO3H3 = NO3H + PO4H3 + Ag =>
2 NO3Ag + H2O + PO3H3 = 2 NO3H + PO4H3 + 2 Ag
CH2OH(CHOH)4COH + Cu(OH)2 = CH2OH(CHOH)4COOH + Cu2O + H2O =>
CH2OH(CHOH)4COH + 2 Cu(OH)2 = CH2OH(CHOH)4COOH + Cu2O + 2 H2O
BeF{2} + Mg = MgF{2} + Be =>
BeF{2} + Mg = MgF{2} + Be
CuSO4*5H2O + BaCl2 = CuCl2 + H2O + BaSO4 =>
CuSO4*5H2O + BaCl2 = CuCl2 + 5 H2O + BaSO4
K3[Al(C2O4)3]*3H2O + KMnO4 + H2SO4 = CO2 + H2O + K2SO4 + Mn + Al =>
7 K3[Al(C2O4)3]*3H2O + 3 KMnO4 + 12 H2SO4 = 42 CO2 + 33 H2O + 12 K2SO4 + 3 Mn + 7 Al
Al(s) + HgBr2(ac) = AlBr3 + Hg =>
2 Al(s) + 3 HgBr2(ac) = 2 AlBr3 + 3 Hg
(NH4)2(Cr2O7)(aq) = Cr2O3(s) + N2(g) + H2O(g) =>
(NH4)2(Cr2O7)(aq) = Cr2O3(s) + N2(g) + 4 H2O(g)
(NH4)2MoO4 + HCl = H2MoO4 + NH4 + Cl =>
(NH4)2MoO4 + 2 HCl = H2MoO4 + 2 NH4 + 2 Cl
PbSO4 + AlCl3 = PbCl2 + Al2(SO4)3 =>
3 PbSO4 + 2 AlCl3 = 3 PbCl2 + Al2(SO4)3
MgCl2KOH = KCl2MgOH =>
MgCl2KOH = KCl2MgOH
KCl + Zn3(Po4)2 = ZnCl2 + K3Po4 =>
6 KCl + Zn3(Po4)2 = 3 ZnCl2 + 2 K3Po4
H2O + Br2 = HBr + HOBr =>
H2O + Br2 = HBr + HOBr
Pb2(NO3)4 + K2CO3 = PbCO3 + KNO3 =>
Pb2(NO3)4 + 2 K2CO3 = 2 PbCO3 + 4 KNO3
Ni(HCO3)2 = NiO + H2O + CO2 =>
Ni(HCO3)2 = NiO + H2O + 2 CO2
SiO2HCl = SiClHO2 =>
SiO2HCl = SiClHO2
H2O + NaNO3 = HNO3 + NaOH =>
H2O + NaNO3 = HNO3 + NaOH
KO2 + CO2 + HO2 = KHCO3 + O2 =>
2 KO2 + 2 CO2 + 2 HO2 = 2 KHCO3 + 3 O2
Ag3PO4 + CaCl2 = AgCl + Ca3(PO4)2 =>
2 Ag3PO4 + 3 CaCl2 = 6 AgCl + Ca3(PO4)2
NaCl + H2O = Cl2 + H2 + NaOH =>
2 NaCl + 2 H2O = Cl2 + H2 + 2 NaOH
Ca(OH)2 + CO2 = Ca(CO3) + H2O =>
Ca(OH)2 + CO2 = Ca(CO3) + H2O
Bilanciare l'equazione di una qualsiasi reazione chimica
Equazioni bilanciate il giorno precedente |
Equazioni bilanciate su11/14/24
Equazioni bilanciate su12/14/23
Lascia un commento sulla tua esperienza con bilanciatore di equazioni chimiche.