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Chemical Equations Balanced on 09/26/09

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Balance equation of any chemical reaction online for free
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HF + Ag = H + AgF =>
HF + Ag = H + AgF

SO3 + NH3 + H2O = (NH4)2SO4 =>
SO3 + 2 NH3 + H2O = (NH4)2SO4

CaCl2(aq) + Cs3PO4(aq) = CaPO4(aq) + Cs3Cl2(aq) =>
CaCl2(aq) + Cs3PO4(aq) = CaPO4(aq) + Cs3Cl2(aq)

S{-2} + I2 = I{-} + S =>
S{-2} + I2 = 2 I{-} + S

NiF2 + Fe2(SO4)3 = NiSO4 + FeF3 =>
3 NiF2 + Fe2(SO4)3 = 3 NiSO4 + 2 FeF3

Cr2O7{-2} + H{+} + {-} = Cr{+3} + H2O =>
Cr2O7{-2} + 14 H{+} + 6e = 2 Cr{+3} + 7 H2O

Ca(OH)2 = CaO + H2O =>
Ca(OH)2 = CaO + H2O

Al + KOH + H2O = K{+} + Al(OH)4{-} + H2 =>
2 Al + 2 KOH + 6 H2O = 2 K{+} + 2 Al(OH)4{-} + 3 H2

B2O3 + HF = BF3 + H2O =>
B2O3 + 6 HF = 2 BF3 + 3 H2O

H2 + O2 = H2O =>
2 H2 + O2 = 2 H2O

Al(OH)3 + H2SO4 = Al2(SO4)3 + H2O =>
2 Al(OH)3 + 3 H2SO4 = Al2(SO4)3 + 6 H2O

Fe + O2 = Fe2O3 =>
4 Fe + 3 O2 = 2 Fe2O3

Y + Ba + Cu + O2 = BaYCuO =>
2 Y + 2 Ba + 2 Cu + O2 = 2 BaYCuO

Y + Ba + Cu + O = BaYCuO =>
Y + Ba + Cu + O = BaYCuO

NaOCl + NH3 = N2H4 + H2O + NaCl =>
NaOCl + 2 NH3 = N2H4 + H2O + NaCl

PbS + HNO3 = Pb(NO3)2 + NO + S + H2O =>
3 PbS + 8 HNO3 = 3 Pb(NO3)2 + 2 NO + 3 S + 4 H2O

N2H4 + OH = N2 + H2O =>
N2H4 + 4 OH = N2 + 4 H2O

PbO2 = PbO + O2 =>
2 PbO2 = 2 PbO + O2

CuSO4 + Zn = Cu + ZnSO4 =>
CuSO4 + Zn = Cu + ZnSO4

K2Cr2O7 + HCl = KCl + CrCl3 + Cl2 + H2O =>
K2Cr2O7 + 14 HCl = 2 KCl + 2 CrCl3 + 3 Cl2 + 7 H2O

Na2S + Cu(NO3)2 = NaNO3 + CuS =>
Na2S + Cu(NO3)2 = 2 NaNO3 + CuS

H{+} + Cr2O7{2-} + FeO = Fe{3+} + Cr{3+} + H2O =>
26 H{+} + Cr2O7{2-} + 6 FeO = 6 Fe{3+} + 2 Cr{3+} + 13 H2O

S + O2 = SO3 =>
2 S + 3 O2 = 2 SO3

FeS2 + O2 + H2O = FeSO4 + H2SO4 =>
2 FeS2 + 7 O2 + 2 H2O = 2 FeSO4 + 2 H2SO4

C3H4O + C5H9NO2 = C8H11NO2 + H2O =>
C3H4O + C5H9NO2 = C8H11NO2 + H2O

NaBr + H3PO4 = Na3PO4 + HBr =>
3 NaBr + H3PO4 = Na3PO4 + 3 HBr

NaClO3 = NaCl + O2 =>
2 NaClO3 = 2 NaCl + 3 O2

CH3OH + O2 = CO2 + H2O =>
2 CH3OH + 3 O2 = 2 CO2 + 4 H2O

MnO4 + H2O = MnO2 + OH =>
MnO4 + 2 H2O = MnO2 + 4 OH

SnCl2 + K2Cr2O7 + HCl = CrCl3 + KCl + SnCl4 + H2O =>
3 SnCl2 + K2Cr2O7 + 14 HCl = 2 CrCl3 + 2 KCl + 3 SnCl4 + 7 H2O

Al + KOH + H2SO4 + H2O = KAl(SO4)2*12H2O + H2 =>
2 Al + 2 KOH + 4 H2SO4 + 22 H2O = 2 KAl(SO4)2*12H2O + 3 H2

C2H5OH + O2 = CO2 + H2O =>
C2H5OH + 3 O2 = 2 CO2 + 3 H2O

Y3 + Ba5 + Cu + O = BaYCuO =>
5 Y3 + 3 Ba5 + 15 Cu + 15 O = 15 BaYCuO

Al(OH)4{-} + H2SO4 = Al(OH)3 + H2O + SO4{-2} =>
2 Al(OH)4{-} + H2SO4 = 2 Al(OH)3 + 2 H2O + SO4{-2}

Y + Ba + Cu + O2 = BaYCuO =>
2 Y + 2 Ba + 2 Cu + O2 = 2 BaYCuO

Y + Ba + Cu + O2 = BaYCuO2 =>
Y + Ba + Cu + O2 = BaYCuO2

S{-2} + I2 = I{-} + S =>
S{-2} + I2 = 2 I{-} + S

FeSO4 + H2SO4 + KMnO4 = Fe2(SO4)3 + K2SO4 + MnSO4 + H2O =>
10 FeSO4 + 8 H2SO4 + 2 KMnO4 = 5 Fe2(SO4)3 + K2SO4 + 2 MnSO4 + 8 H2O

C10H7NO2 + O2 = CO2 + H2O + N2 =>
4 C10H7NO2 + 43 O2 = 40 CO2 + 14 H2O + 2 N2

Ca(OH)2 + Al2(SO4)3 = CaSO4 + Al(OH)3 =>
3 Ca(OH)2 + Al2(SO4)3 = 3 CaSO4 + 2 Al(OH)3

SrH2 + H2O = Sr(OH)2 + H2 =>
SrH2 + 2 H2O = Sr(OH)2 + 2 H2

Al(OH)3 + H2SO4 = Al{+3} + SO4{-2} + H2O =>
2 Al(OH)3 + 3 H2SO4 = 2 Al{+3} + 3 SO4{-2} + 6 H2O

Bi + OH = BiO3 + H2O =>
Bi + 6 OH = BiO3 + 3 H2O

Cu + HNO3 = Cu(NO3)2 + NO2 + H2O =>
Cu + 4 HNO3 = Cu(NO3)2 + 2 NO2 + 2 H2O

Ca(OH)2 + Al2(SO4)3 = CaSO4 + Al(OH)3 =>
3 Ca(OH)2 + Al2(SO4)3 = 3 CaSO4 + 2 Al(OH)3

H2O + CO2 = C7H8 + O2 =>
4 H2O + 7 CO2 = C7H8 + 9 O2

Mg + Fe2O3 = Fe + MgO =>
3 Mg + Fe2O3 = 2 Fe + 3 MgO

C + K2Cr2O7 + H2SO4 = CO2 + K2SO4 + Cr2(SO4)3 + H2O =>
3 C + 2 K2Cr2O7 + 8 H2SO4 = 3 CO2 + 2 K2SO4 + 2 Cr2(SO4)3 + 8 H2O

Li + N2 = LiN3 =>
2 Li + 3 N2 = 2 LiN3

Cu + H{+} + NO3{-} = Cu{2+} + NO2 + H2O =>
Cu + 4 H{+} + 2 NO3{-} = Cu{2+} + 2 NO2 + 2 H2O

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Balance equation of any chemical reaction online for free
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