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Chemical Equations Balanced on 08/07/22

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Balance equation of any chemical reaction online for free
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Zn(NO3)2*6H2O + Eu(NO3)3*6H2O + Na2Mo1O4*2H2O = Zn099MoO4Eu001 + N2 + O2 + Na2 + H2 =>
198 Zn(NO3)2*6H2O + 2.0000000000001Eu(NO3)3*6H2O + 2 Na2Mo1O4*2H2O = 2 Zn099MoO4Eu001 + 201 N2 + 1205 O2 + 2 Na2 + 1204 H2

Na + Cl = NaCl =>
Na + Cl = NaCl

Zn + I2 = ZnI2 =>
Zn + I2 = ZnI2

CO(g) + H2(g) = C8H18(l) + H2O =>
8 CO(g) + 17 H2(g) = C8H18(l) + 8 H2O

Zn(NO3)2*6H2O + Eu(NO3)3*6H2O + Na2MoO4*2H2O = Zn099MoO4Eu001 + N2 + O2 + Na2 + H2 =>
198 Zn(NO3)2*6H2O + 2.0000000000001Eu(NO3)3*6H2O + 2 Na2MoO4*2H2O = 2 Zn099MoO4Eu001 + 201 N2 + 1205 O2 + 2 Na2 + 1204 H2

Mg + S = MgS =>
Mg + S = MgS

Zn(NO3)2*6H2O + Eu(NO3)3*6H2O + Na2MoO4*2H2O = Zn098MoO4Eu002 + N2 + O2 + Na2 + H2 =>
98 Zn(NO3)2*6H2O + 2 Eu(NO3)3*6H2O + Na2MoO4*2H2O = Zn098MoO4Eu002 + 101 N2 + 604 O2 + Na2 + 602 H2

C4H10 + O2 = CO2 + H2O =>
2 C4H10 + 13 O2 = 8 CO2 + 10 H2O

LiOH + H2SO4 = Li2SO4 + H2O =>
2 LiOH + H2SO4 = Li2SO4 + 2 H2O

ZnCO3 + H2SO4 = ZnSO4 + H2O + CO2 =>
ZnCO3 + H2SO4 = ZnSO4 + H2O + CO2

ZnCO3 + H2SO4 = ZnSO4 + H2O + CO2 =>
ZnCO3 + H2SO4 = ZnSO4 + H2O + CO2

Zn(NO3)2*6H2O + Eu(NO3)3*6H2O + Na2MoO4*2H2O = Zn098Mo100O4Eu002 + N2 + O2 + Na2 + H2 =>
98 Zn(NO3)2*6H2O + 2 Eu(NO3)3*6H2O + 100 Na2MoO4*2H2O = Zn098Mo100O4Eu002 + 101 N2 + 901 O2 + 100 Na2 + 800 H2

Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2

Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

Br2 + S + H2O = HBr + H2SO4 =>
3 Br2 + S + 4 H2O = 6 HBr + H2SO4

Zn(NO3)2*6H2O + Eu(NO3)3*6H2O + Na2MoO4*2H2O = Zn098Mo100O4Eu002 + N2 + O2 + Na2 + H2 =>
98 Zn(NO3)2*6H2O + 2 Eu(NO3)3*6H2O + 100 Na2MoO4*2H2O = Zn098Mo100O4Eu002 + 101 N2 + 901 O2 + 100 Na2 + 800 H2

Fe + SO4 = FeSO4 =>
Fe + SO4 = FeSO4

H2SO4 + Pb(OH)4 = Pb(SO4)2 + H2O =>
2 H2SO4 + Pb(OH)4 = Pb(SO4)2 + 4 H2O

Zn(NO3)2*6H2O + Eu(NO3)3*6H2O + Na2MoO4*2H2O = Zn099Mo100O4Eu001 + N2 + O2 + Na2 + H2 =>
198 Zn(NO3)2*6H2O + 2.0000000000003Eu(NO3)3*6H2O + 200 Na2MoO4*2H2O = 2 Zn099Mo100O4Eu001 + 201 N2 + 1799 O2 + 200 Na2 + 1600 H2

Al + HCl = AlCl3 + H2 =>
2 Al + 6 HCl = 2 AlCl3 + 3 H2

Zn(NO3)2*6H2O + Eu(NO3)3*6H2O + Na2MoO4*2H2O = Zn098Mo100O4Eu002 + N2 + O2 + Na2 + H2 =>
98 Zn(NO3)2*6H2O + 2 Eu(NO3)3*6H2O + 100 Na2MoO4*2H2O = Zn098Mo100O4Eu002 + 101 N2 + 901 O2 + 100 Na2 + 800 H2

Zn + HNO3 = Zn(NO3)2 + H2 =>
Zn + 2 HNO3 = Zn(NO3)2 + H2

Ca3(PO4)2 + H2SO4 = CaSO4 + Ca(H2PO4)2 =>
Ca3(PO4)2 + 2 H2SO4 = 2 CaSO4 + Ca(H2PO4)2

C2H5OH + O2 = CO2 + H2O =>
C2H5OH + 3 O2 = 2 CO2 + 3 H2O

OC = OC =>
OC = OC

Zn(NO3)2*6H2O + Eu(NO3)3*6H2O + Na2MoO4*2H2O = Zn097Mo100O4Eu003 + N2 + O2 + Na2 + H2 =>
194 Zn(NO3)2*6H2O + 6 Eu(NO3)3*6H2O + 200 Na2MoO4*2H2O = 2 Zn097Mo100O4Eu003 + 203 N2 + 1805 O2 + 200 Na2 + 1600 H2

H3PO4 + HCl = PCl5 + H2O =>
H3PO4 + 5 HCl = PCl5 + 4 H2O

OC = OC =>
OC = OC

Fe + H2SO4 = Fe2(SO4)3 + H2 =>
2 Fe + 3 H2SO4 = Fe2(SO4)3 + 3 H2

Fe + H2SO4 = Fe2(SO4)3 + H2 =>
2 Fe + 3 H2SO4 = Fe2(SO4)3 + 3 H2

C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O

Mg + H3PO4 = Mg3(PO4)2 + H2 =>
3 Mg + 2 H3PO4 = Mg3(PO4)2 + 3 H2

KOH + H3PO4 = K3PO4 + H2O =>
3 KOH + H3PO4 = K3PO4 + 3 H2O

SnO2 + H2 = Sn + H2O =>
SnO2 + 2 H2 = Sn + 2 H2O

NH3 + O2 = NO + H2O =>
4 NH3 + 5 O2 = 4 NO + 6 H2O

KNO3 + H2CO3 = K2CO3 + HNO3 =>
2 KNO3 + H2CO3 = K2CO3 + 2 HNO3

Sn + HCl = SnCl2 + H2 =>
Sn + 2 HCl = SnCl2 + H2

B2Br6 + HNO3 = B(NO3)3 + HBr =>
B2Br6 + 6 HNO3 = 2 B(NO3)3 + 6 HBr

BaO + As2O5 = Ba3(AsO4)2 =>
3 BaO + As2O5 = Ba3(AsO4)2

Fe2O3 + CO = Fe + CO2 =>
Fe2O3 + 3 CO = 2 Fe + 3 CO2

Al + CuSO4 = Al2(SO4)3 + Cu =>
2 Al + 3 CuSO4 = Al2(SO4)3 + 3 Cu

ZnS + AlP = Zn3P2 + Al2S3 =>
3 ZnS + 2 AlP = Zn3P2 + Al2S3

SeCl6 + O2 = SeO2 + Cl2 =>
SeCl6 + O2 = SeO2 + 3 Cl2

Ag3PO4 = Ag + PO4 =>
Ag3PO4 = 3 Ag + PO4

H3PO4 + NH3 = (NH4)3PO4 =>
H3PO4 + 3 NH3 = (NH4)3PO4

NH4NO3 = N2O + H2O =>
NH4NO3 = N2O + 2 H2O

FeCl3(aq) + KI(aq) = KCl(aq) + FeI2(aq) + I2(aq) =>
2 FeCl3(aq) + 6 KI(aq) = 6 KCl(aq) + 2 FeI2(aq) + I2(aq)

NH3 + HNO3 = NH4NO3 =>
NH3 + HNO3 = NH4NO3

FeCl3 + NaOH = Fe(OH)3 + NaCl =>
FeCl3 + 3 NaOH = Fe(OH)3 + 3 NaCl

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Balance equation of any chemical reaction online for free
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