Equations balanced on the previous day | Equations balanced on the next day |
2 Si + 2 HNO3 = 2 NO + 2 SiO2 + H2
[Co(NH3)5Cl]{+2} + H2O = [Co(NH3)5(H2O)]{+3} + Cl{-} =>
[Co(NH3)5Cl]{+2} + H2O = [Co(NH3)5(H2O)]{+3} + Cl{-}
Mg + Cr = Mg2Cr3 =>
2 Mg + 3 Cr = Mg2Cr3
HgS + HNO3 + HCl = HgCl4 + H2SO4 + NO + H2O =>
3 HgS + 10 HNO3 + 12 HCl = 3 HgCl4 + 3 H2SO4 + 10 NO + 8 H2O
NaBr + MnO2 + H2SO4 = NaHSO4 + MnHSO4 + H2O + Br2 =>
6 NaBr + 2 MnO2 + 8 H2SO4 = 6 NaHSO4 + 2 MnHSO4 + 4 H2O + 3 Br2
PH3 + H2SO4 = (PH3)SO4 + H2 =>
PH3 + H2SO4 = (PH3)SO4 + H2
C6H10 + H2SO4 + KMnO4 = K2SO4 + MnSO4 + H2O + C6H10O4 =>
5 C6H10 + 12 H2SO4 + 8 KMnO4 = 4 K2SO4 + 8 MnSO4 + 12 H2O + 5 C6H10O4
Zn(s) + MnO2(s) + H2O(l) = Zn(OH)2 + Mn2O3 =>
Zn(s) + 2 MnO2(s) + H2O(l) = Zn(OH)2 + Mn2O3
CuSO4 + Zn = OZn + Cu(SO2) =>
CuSO4 + 2 Zn = 2 OZn + Cu(SO2)
Ra + HNO3 = Ra(NO3)2 + NH3 + H2O =>
4 Ra + 9 HNO3 = 4 Ra(NO3)2 + NH3 + 3 H2O
KClO4 = KCl + O(g) =>
KClO4 = KCl + 4 O(g)
H + CrO4{2-} + Cd{2+} = Cd + Cr{3+} + H2O =>
16 H + 2 CrO4{2-} + 5 Cd{2+} = 5 Cd + 2 Cr{3+} + 8 H2O
Ca(OH)2 + Al2(OH)3 = Al(OH)3 + CaOH =>
3 Ca(OH)2 + Al2(OH)3 = 2 Al(OH)3 + 3 CaOH
AI + Ca2CO3 = Ca + AI(CO3)3 =>
AI + 3 Ca2CO3 = 6 Ca + AI(CO3)3
AgI + Na2S = Ag2S + NaI =>
2 AgI + Na2S = Ag2S + 2 NaI
Zn(s) + MnO2(s) + H2O(l) = Zn(OH)2 + Mn2O3 =>
Zn(s) + 2 MnO2(s) + H2O(l) = Zn(OH)2 + Mn2O3
(NH4)2S2O8 + KI = I2 + K2SO4 + (NH4)2SO4 =>
(NH4)2S2O8 + 2 KI = I2 + K2SO4 + (NH4)2SO4
FeBr{+3} + KCl = FeCl{+3} + KBr =>
FeBr{+3} + KCl = FeCl{+3} + KBr
C2H6S + H2O2 = C2H6OS + H2O =>
C2H6S + H2O2 = C2H6OS + H2O
H2O + A1 + Ba(NO3)2 = Ba(OH)2 + A1(OH)3 + NH3 =>
36 H2O + 16 A1 + 3 Ba(NO3)2 = 3 Ba(OH)2 + 16 A1(OH)3 + 6 NH3
Fe2 + PO4 = FePO4 =>
Fe2 + 2 PO4 = 2 FePO4
Cu(CN)2 = CuCN + C2N2 =>
2 Cu(CN)2 = 2 CuCN + C2N2
KIO3 + SnCl2 + HCl = SnCl4 + KCl + I2 + H2O =>
2 KIO3 + 5 SnCl2 + 12 HCl = 5 SnCl4 + 2 KCl + I2 + 6 H2O
CH2 + C600H774N952O2262 = CO2 + H2O + N2 =>
225 CH2 + C600H774N952O2262 = 825 CO2 + 612 H2O + 476 N2
U{4+} + Ce{4+} = U{10+} + Ce{3+} =>
U{4+} + 6 Ce{4+} = U{10+} + 6 Ce{3+}
NaOH + H2 + Cl2 = NaClH2O =>
2 NaOH + H2 + Cl2 = 2 NaClH2O
Na3PO4 + Ca = Ca3(PO4) + Na =>
Na3PO4 + 3 Ca = Ca3(PO4) + 3 Na
NaOH + H2 + Cl2 = NaClH2O =>
2 NaOH + H2 + Cl2 = 2 NaClH2O
C10H15NO + HI + P = C10H15N + PH3 + IO3 =>
9 C10H15NO + 3 HI + P = 9 C10H15N + PH3 + 3 IO3
Fe2O3 + C = Fe2 + CO2 =>
2 Fe2O3 + 3 C = 2 Fe2 + 3 CO2
H2S + KMnO4 + HNO3 = S + MnNO3 + KNO3 + H2O =>
3 H2S + KMnO4 + 2 HNO3 = 3 S + MnNO3 + KNO3 + 4 H2O
C6H8O7 + Cu(NO3)23H20 + Fe(N03)39H20 + Zn(NO3)26H20 = Cu05Zn05Fe2O4 + H2O + CO2 + N2 =>
1222 C6H8O7 + 89.999999999999Cu(NO3)23H20 + 36 Fe(N03)39H20 + 89.999999999998Zn(NO3)26H20 = 18 Cu05Zn05Fe2O4 + 7047.9999999999H2O + 7331.9999999999CO2 + 4311 N2
Zn + H2MoO4 + H{+} = Zn{+2} + Mo{+3} + H2O =>
3 Zn + 2 H2MoO4 + 12 H{+} = 3 Zn{+2} + 2 Mo{+3} + 8 H2O
CaH2O = CaOH + H =>
CaH2O = CaOH + H
KNO3 + C = K3CO3 + CO + N2 =>
6 KNO3 + 14 C = 2 K3CO3 + 12 CO + 3 N2
H + CrO4{2-} + Cd{2+} = Cd + Cr{3+} + H2O =>
16 H + 2 CrO4{2-} + 5 Cd{2+} = 5 Cd + 2 Cr{3+} + 8 H2O
HNO3 + Pb = HPb + NO3 =>
HNO3 + Pb = HPb + NO3
Fe + S = S2Fe2 =>
2 Fe + 2 S = S2Fe2
HClO3 + H2SO3 = H2SO4 + HCl =>
HClO3 + 3 H2SO3 = 3 H2SO4 + HCl
Cu + FeCl3 = CuCl3 + Fe =>
Cu + FeCl3 = CuCl3 + Fe
NH4OH + H3O = NH4 + H2O =>
NH4OH + H3O = NH4 + 2 H2O
CH3CH2OH + CH4 = CH3CH2OCH3 + H2 =>
CH3CH2OH + CH4 = CH3CH2OCH3 + H2
NaMnO4 + KI + HCl = MnCl2 + I2 + KCl + NaCl + H2O =>
2 NaMnO4 + 10 KI + 16 HCl = 2 MnCl2 + 5 I2 + 10 KCl + 2 NaCl + 8 H2O
CuCO3() + H2SO4(aq) = CuSO4(a) + H2O() + CO2(g) =>
CuCO3() + H2SO4(aq) = CuSO4(a) + H2O() + CO2(g)
H3AsO3 + OH{-} = AsO3{3-} + H2O =>
H3AsO3 + 3 OH{-} = AsO3{3-} + 3 H2O
Fe2 + PO4 = FePO4 =>
Fe2 + 2 PO4 = 2 FePO4
BaCI2 + F2 = BaF2 + CI2 =>
BaCI2 + F2 = BaF2 + CI2
Fe2 + PO4 = FePO4 =>
Fe2 + 2 PO4 = 2 FePO4
KClO3 + KI + H2O = KOH + HCl + I2 =>
KClO3 + 6 KI + 4 H2O = 7 KOH + HCl + 3 I2
HC6H5COO + NaOH = HOH + NaC6H5COO =>
HC6H5COO + NaOH = HOH + NaC6H5COO
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/18/23
Equations balanced on 12/18/22
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