Equations balanced on the previous day | Equations balanced on the next day |
CaB4O7*10H2O + 2 HCl = 4 H3BO3 + CaCl2 + 5 H2O
CH3CH2OHCOOH(aq) + KOH(aq) = CH3CH2OHCOOK(aq) + H2O =>
CH3CH2OHCOOH(aq) + KOH(aq) = CH3CH2OHCOOK(aq) + H2O
Al + S = Al2S3 =>
2 Al + 3 S = Al2S3
HSO4{-} + e + H{+} = S2O6{2-} + H2O =>
2 HSO4{-} + 2e + 2 H{+} = S2O6{2-} + 2 H2O
H2O2 + NaOH = Na2O2 + H2O =>
H2O2 + 2 NaOH = Na2O2 + 2 H2O
Cl2 + BaBr2 = Br2Cl2 + Ba =>
Cl2 + BaBr2 = Br2Cl2 + Ba
MgO + NaCl = Na2O + MgCl2 =>
MgO + 2 NaCl = Na2O + MgCl2
MnSO4 + PbO2 + HNO3 = HMnO4 + Pb(NO3)2 + PbSO4(s) + H2O =>
2 MnSO4 + 5 PbO2 + 6 HNO3 = 2 HMnO4 + 3 Pb(NO3)2 + 2 PbSO4(s) + 2 H2O
Sc + H3O{+} + H2O = (Sc(H2O)6){3+} + H2 =>
2 Sc + 6 H3O{+} + 6 H2O = 2(Sc(H2O)6){3+} + 3 H2
CH3CH2OH + NaOH = CH3ONa + H2O =>
CH3CH2OH + 2 NaOH = 2 CH3ONa + H2O
Al + S = Al2S3 =>
2 Al + 3 S = Al2S3
H3PO4 + RbOH = H2O + Rb3PO4 =>
H3PO4 + 3 RbOH = 3 H2O + Rb3PO4
C2H5OH + KMnO4 + HCl = KCl + MnCl2 + CH3COOH + H2O =>
5 C2H5OH + 4 KMnO4 + 12 HCl = 4 KCl + 4 MnCl2 + 5 CH3COOH + 11 H2O
Zn{+} + NO2{-} + H{+} = Zn{2+} + NH4{+} + H2O =>
6 Zn{+} + NO2{-} + 8 H{+} = 6 Zn{2+} + NH4{+} + 2 H2O
Cd(s) + S(s) = CdS =>
Cd(s) + S(s) = CdS
CO3{-2} + CH4O = C2H4O2 + H2O + e =>
CO3{-2} + 3 CH4O = 2 C2H4O2 + 2 H2O + 2e
Cl2 + BaBr2 = Br2Cl2 + Ba =>
Cl2 + BaBr2 = Br2Cl2 + Ba
RbOH + H3PO4 = H3Rb + PO4OH =>
RbOH + H3PO4 = H3Rb + PO4OH
CH2O2 + KMnO7 + H2SO4 = CO2 + MnSO4 + K2SO4 + H2O =>
11 CH2O2 + 2 KMnO7 + 3 H2SO4 = 11 CO2 + 2 MnSO4 + K2SO4 + 14 H2O
C5H12O + CH3COOH = C7H14O2 + H3O =>
30 C5H12O + 23 CH3COOH = 28 C7H14O2 + 20 H3O
Fe(HCO3)2 + O2 + Ca(OH)2 = Fe(OH)3 + CaCO3 + H2O =>
4 Fe(HCO3)2 + O2 + 8 Ca(OH)2 = 4 Fe(OH)3 + 8 CaCO3 + 6 H2O
CH2OH + K2Cr2O7 + H2SO4 = CH3COOH + Cr2(SO4)3 + K2SO4 + H2O =>
6 CH2OH + K2Cr2O7 + 4 H2SO4 = 3 CH3COOH + Cr2(SO4)3 + K2SO4 + 7 H2O
NaI + CoCl2(H2O)6 + [NH4]Cl + NH3 + O2 = [CoI(NH3)5]Cl2 + H2O + NaCl =>
4 NaI + 4 CoCl2(H2O)6 + 4[NH4]Cl + 16 NH3 + O2 = 4[CoI(NH3)5]Cl2 + 26 H2O + 4 NaCl
Ti + Fe2(CO3)3 = Ti(CO3)3 + Fe =>
Ti + Fe2(CO3)3 = Ti(CO3)3 + 2 Fe
I2 + HSO3{-} + H2O = I{-} + SO4{2-} + H{+} =>
I2 + HSO3{-} + H2O = 2 I{-} + SO4{2-} + 3 H{+}
K2Cr2O7(aq) + FeSO4(aq) + H2SO4 = Fe2(SO4)3(aq) + Cr2(SO4)3(aq) + K2SO4 + H2O =>
K2Cr2O7(aq) + 6 FeSO4(aq) + 7 H2SO4 = 3 Fe2(SO4)3(aq) + Cr2(SO4)3(aq) + K2SO4 + 7 H2O
BaCO3 + Na2SiO3 = Na2CO3 + BaSiO3 =>
BaCO3 + Na2SiO3 = Na2CO3 + BaSiO3
NaCH3COO + H2SO4 = NaHSO4 + HCH3COO =>
NaCH3COO + H2SO4 = NaHSO4 + HCH3COO
Ni2 + S3 = NiS =>
3 Ni2 + 2 S3 = 6 NiS
KCIO3 + MnO2 = KO2 + MnCIO3 =>
KCIO3 + MnO2 = KO2 + MnCIO3
NaMnO4 + Na2S + H2SO4 = MnSO4 + Na2SO4 + H2O =>
8 NaMnO4 + 5 Na2S + 12 H2SO4 = 8 MnSO4 + 9 Na2SO4 + 12 H2O
KNO2 + KMnO4 + H2SO4 = MnSO4 + K2SO4 + KNO3 + H2O =>
5 KNO2 + 2 KMnO4 + 3 H2SO4 = 2 MnSO4 + K2SO4 + 5 KNO3 + 3 H2O
CaO + P2O5 = Ca3(PO4)2 =>
3 CaO + P2O5 = Ca3(PO4)2
NaC + Pb(NO3)2 = PbC2 + NaNO3 =>
2 NaC + Pb(NO3)2 = PbC2 + 2 NaNO3
HCl + K4(Fe(CN)6) + KMnO4 = K3(Fe(CN)6) + KCl + MnO2 + H2O =>
4 HCl + 3 K4(Fe(CN)6) + KMnO4 = 3 K3(Fe(CN)6) + 4 KCl + MnO2 + 2 H2O
SCl + CS2 = CCl + S =>
SCl + CS2 = CCl + 3 S
NaF + Ca = NaCa + F =>
NaF + Ca = NaCa + F
lithium + sodiumsulfide = sodium + lithiumsulfide =>
2 Li + Na2S = 2 Na + Li2S
Pb(NO3)2 + (Na)3PO4 = Pb3(PO4)2 + NaNO3 =>
3 Pb(NO3)2 + 2(Na)3PO4 = Pb3(PO4)2 + 6 NaNO3
FeCl2 + KMnO4 = Fe(MnO4)2 + KCl =>
FeCl2 + 2 KMnO4 = Fe(MnO4)2 + 2 KCl
TiC + O2 = Ti4O7 + CO2 =>
8 TiC + 15 O2 = 2 Ti4O7 + 8 CO2
H3AsO3 + NO3 = H3AsO4 + NO =>
2 H3AsO3 + NO3 = 2 H3AsO4 + NO
(R3NH{+})2SO4{2-}] + UO2(SO4)3{4-} = [(R3NH{+})2UO2(SO4)3{4-}] + SO4{2-} =>
(R3NH{+})2SO4{2-}] + UO2(SO4)3{4-} = [(R3NH{+})2UO2(SO4)3{4-}] + SO4{2-}
SrN6 + NH4Cl + P3N5 = SrP3N5NH + N2 + SrCl2 =>
9 SrN6 + 2 NH4Cl + 8 P3N5 = 8 SrP3N5NH + 24 N2 + SrCl2
Li + H2SO4 = LiHSO4 + SO2 + H2O =>
2 Li + 3 H2SO4 = 2 LiHSO4 + SO2 + 2 H2O
CrCl3 + H2O2 = HCl + CrO3 =>
2 CrCl3 + 3 H2O2 = 6 HCl + 2 CrO3
CrBr3 + NaCO3 = Cr(CO3)3 + NaBr =>
CrBr3 + 3 NaCO3 = Cr(CO3)3 + 3 NaBr
CrBr3 + NaCO3 = Cr(CO3)3 + NaBr =>
CrBr3 + 3 NaCO3 = Cr(CO3)3 + 3 NaBr
CrBr3 + NaCO3 = Cr(CO3)3 + NaBr =>
CrBr3 + 3 NaCO3 = Cr(CO3)3 + 3 NaBr
CCl4 + H2O = C(OH)4 + HCl =>
CCl4 + 4 H2O = C(OH)4 + 4 HCl
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/24/23
Equations balanced on 12/24/22
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