Equations balanced on the previous day | Equations balanced on the next day |
Sb2O3 + 3 CO = 2 Sb + 3 CO2
Cr(NO3)3*9H2 + Y(NO3)3*6H2O + CH4N2O = YCrO3 + N2 + CO2 + H2O =>
Cr(NO3)3*9H2 + Y(NO3)3*6H2O + 2 CH4N2O = YCrO3 + 5 N2 + 2 CO2 + 19 H2O
Cr2O3 + Na2CO3 = Na2Cr4O7 + CO2 =>
2 Cr2O3 + Na2CO3 = Na2Cr4O7 + CO2
NaBr + V = VBr3 + Na =>
3 NaBr + V = VBr3 + 3 Na
Cl2 + CrI3 + KOH = KCl + KIO3 + K2Cr2O7 + H2O =>
21 Cl2 + 2 CrI3 + 50 KOH = 42 KCl + 6 KIO3 + K2Cr2O7 + 25 H2O
NaBr + V = VBr3 + Na =>
3 NaBr + V = VBr3 + 3 Na
K2CO3 + NaOH = KOH + Na2CO3 =>
K2CO3 + 2 NaOH = 2 KOH + Na2CO3
K2SO4 + CuCl2 = KCl + CuSO4 =>
K2SO4 + CuCl2 = 2 KCl + CuSO4
C3H8 + O2(g) = CO2(g) + H2O =>
C3H8 + 5 O2(g) = 3 CO2(g) + 4 H2O
V2(HPO4)3 + Nb2(Cr2O7)5 + Nb2(SO4)5 + H3PO4 = V2(SO4)7 + Cr2(HPO4)3 + Nb2(HPO4)5 + H2O =>
15 V2(HPO4)3 + 4 Nb2(Cr2O7)5 + 21 Nb2(SO4)5 + 140 H3PO4 = 15 V2(SO4)7 + 20 Cr2(HPO4)3 + 25 Nb2(HPO4)5 + 140 H2O
NaBr + V = VBr3 + Na =>
3 NaBr + V = VBr3 + 3 Na
BCl3 + BF3 = BFCl2 =>
2 BCl3 + BF3 = 3 BFCl2
NaBr + V = VBr3 + Na =>
3 NaBr + V = VBr3 + 3 Na
Na2SO4 + C = Na2S + CO =>
Na2SO4 + 4 C = Na2S + 4 CO
HNO3 + NAOH(aq) = NANO3(aq) + H2O(l) =>
HNO3 + NAOH(aq) = NANO3(aq) + H2O(l)
C10H18O3N + O2 = CO2 + H2O + NH3 =>
4 C10H18O3N + 49 O2 = 40 CO2 + 30 H2O + 4 NH3
V2O5 + H2C2O4*H2O = VOC2O4 + CO2 + H2O =>
V2O5 + 3 H2C2O4*H2O = 2 VOC2O4 + 2 CO2 + 6 H2O
MnO4 + K2SO3 + KOH = K2MnO4 + KSO4 + H2O =>
3 MnO4 + 2 K2SO3 + 4 KOH = 3 K2MnO4 + 2 KSO4 + 2 H2O
NaBr + V = VBr3 + Na =>
3 NaBr + V = VBr3 + 3 Na
SnCl4 + AlAsO4 = Sn3(AsO4)4 + AlCl3 =>
3 SnCl4 + 4 AlAsO4 = Sn3(AsO4)4 + 4 AlCl3
CrCl3 + H2O2 + NaOH = H2O + Na2CrO4 + NaCl =>
2 CrCl3 + 3 H2O2 + 10 NaOH = 8 H2O + 2 Na2CrO4 + 6 NaCl
NH4I(aq) + NaOH(aq) = NaI(aq) + NH4OH(g) =>
NH4I(aq) + NaOH(aq) = NaI(aq) + NH4OH(g)
NaBr + V = VBr3 + Na =>
3 NaBr + V = VBr3 + 3 Na
HCO2HNaOH = HCO2NaH2O =>
HCO2HNaOH = HCO2NaH2O
HCl + Na2CO3 = Na2Cl + CO3H =>
HCl + Na2CO3 = Na2Cl + CO3H
HBr + K2CO4 = H2CO4 + KBr =>
2 HBr + K2CO4 = H2CO4 + 2 KBr
H2NCOONH4 = CO2 + NH3 =>
H2NCOONH4 = CO2 + 2 NH3
Na2HCO3 + Fe2(SO4)3 = Na2SO4 + Fe2(HCO3)3 =>
3 Na2HCO3 + Fe2(SO4)3 = 3 Na2SO4 + Fe2(HCO3)3
Mg + ZnSO4 = MgSO4 + Zn =>
Mg + ZnSO4 = MgSO4 + Zn
K4Fe(CN)6 + KMnO4 + H2SO4 = KHSO4 + FeSO4 + MnSO4 + HNO3 + CO2 + H2O =>
K4Fe(CN)6 + 12 KMnO4 + 29 H2SO4 = 16 KHSO4 + FeSO4 + 12 MnSO4 + 6 HNO3 + 6 CO2 + 18 H2O
C2H4(g) + CuO(s) = Cu(s) + CO2(g) + H2O =>
C2H4(g) + 6 CuO(s) = 6 Cu(s) + 2 CO2(g) + 2 H2O
Fe{2+} + O2 + H{+} = Fe{3}{+} + H2O =>
4 Fe{2+} + O2 + 4 H{+} = 4 Fe{3}{+} + 2 H2O
KCO3(s) + HCl(aq) = KCl2(aq) + H2O(l) + CO2(g) =>
KCO3(s) + 2 HCl(aq) = KCl2(aq) + H2O(l) + CO2(g)
sodiumiodide + potassiumnitrate = potassiumiodide + sodiumnitrate =>
NaI + KNO3 = KI + NaNO3
CuSO4 + NaHSO3 = Cu3(SO3)2 + NaHSO4 + SO2 =>
3 CuSO4 + 4 NaHSO3 = Cu3(SO3)2 + 4 NaHSO4 + SO2
CoCl2 + NH4Cl = Co(NH3)2Cl2 + HCl =>
CoCl2 + 2 NH4Cl = Co(NH3)2Cl2 + 2 HCl
Mg + ZnSO4 = MgSO4 + Zn =>
Mg + ZnSO4 = MgSO4 + Zn
NH4FeS2O8 + NaOH = FeO2H + Na2SO4 + NH3 + H2O =>
NH4FeS2O8 + 4 NaOH = FeO2H + 2 Na2SO4 + NH3 + 2 H2O
Hg2(NO3)2(aq) + NH4ClO3(aq) = NH4NO3 + HgClO3 =>
Hg2(NO3)2(aq) + 2 NH4ClO3(aq) = 2 NH4NO3 + 2 HgClO3
CoI2 + Mg(NO3)2 = Co(NO3)2 + MgI2 =>
CoI2 + Mg(NO3)2 = Co(NO3)2 + MgI2
HCI(aq) + KOH(aq) = KCI(l) + H2O(l) =>
HCI(aq) + KOH(aq) = KCI(l) + H2O(l)
OC3H6 + O2 = CO2 + H2O =>
OC3H6 + 4 O2 = 3 CO2 + 3 H2O
KCl0O3 = KClO2 + O2 =>
2 KCl0O3 = 2 KClO2 + O2
H3O + HMnO4 = MnO2 + H2O =>
3 H3O + HMnO4 = MnO2 + 5 H2O
Mg(s) + Cu(aq)NO3 = Mg(NO3)2(aq) + Cu(s) =>
Mg(s) + 2 Cu(aq)NO3 = Mg(NO3)2(aq) + 2 Cu(s)
Cl2 + P = Cl5P =>
5 Cl2 + 2 P = 2 Cl5P
Zn + HF = ZnF2 + H2 =>
Zn + 2 HF = ZnF2 + H2
C3H8O3 + H2 = CH4 + H2O =>
C3H8O3 + 5 H2 = 3 CH4 + 3 H2O
Ne + O2 = Ne2O2 =>
2 Ne + O2 = Ne2O2
C300H602 + O2 = CO2 + H2O =>
2 C300H602 + 901 O2 = 600 CO2 + 602 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 11/30/23
Equations balanced on 12/30/22
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