Equations balanced on the previous day | Equations balanced on the next day |
2 NaNO3 + H2SO4 = Na2SO4 + 2 HNO3
Cu2FeS2 + HNO3 = Cu(NO3)2 + Fe(NO3)3 + H2SO4 + NO2 + H2O =>
Cu2FeS2 + 26 HNO3 = 2 Cu(NO3)2 + Fe(NO3)3 + 2 H2SO4 + 19 NO2 + 11 H2O
NaOH + Pd(NO3)2 = NaNO3 + Pd(OH)2 =>
2 NaOH + Pd(NO3)2 = 2 NaNO3 + Pd(OH)2
Zn + O2 = ZnO2 =>
Zn + O2 = ZnO2
Mn3 + P2 = Mn3P2 =>
Mn3 + P2 = Mn3P2
Cl + HMg = ClMg + H2 =>
2 Cl + 2 HMg = 2 ClMg + H2
BaBr2(aq) + Na2SO4(aq) = Na2Br2 + BaSO4 =>
BaBr2(aq) + Na2SO4(aq) = Na2Br2 + BaSO4
OH{-} + C + SO4{2+} = CO2 + SO2 + H2O =>
4 OH{-} + 3 C + 2 SO4{2+} = 3 CO2 + 2 SO2 + 2 H2O
C5H8O3 + C12H18N4O7P2S = C16H26N4O8P2S + CO2 =>
C5H8O3 + C12H18N4O7P2S = C16H26N4O8P2S + CO2
Cr2O3 + Si = Cr + SiO2 =>
2 Cr2O3 + 3 Si = 4 Cr + 3 SiO2
KL + Cu(NO3)2 = CuL2 + KNO3 =>
2 KL + Cu(NO3)2 = CuL2 + 2 KNO3
KMnO4 + H2C2O4 + NaOH = MnO2 + Na2CO3 + K2CO3 + H2O =>
2 KMnO4 + 3 H2C2O4 + 10 NaOH = 2 MnO2 + 5 Na2CO3 + K2CO3 + 8 H2O
S8 + NO3{-} + H{+} = S4O62{-} + NO2 + H2O(inacid) =>
S8 + 246 NO3{-} + 244 H{+} = 2 S4O62{-} + 246 NO2 + 122 H2O(inacid)
FeSO4*7H2O + NaOH = FeO + Na2SO4 + H2O =>
FeSO4*7H2O + 2 NaOH = FeO + Na2SO4 + 8 H2O
CH4 + F2 + Cl2 = C2F4Cl4 + H4 =>
2 CH4 + 2 F2 + 2 Cl2 = C2F4Cl4 + 2 H4
Al2S3O12 + CaO2H2 = AlO3H3 + CaSO4 =>
Al2S3O12 + 3 CaO2H2 = 2 AlO3H3 + 3 CaSO4
CH3COOH + C2H5OH = COOC2H5 + H2O =>
5 CH3COOH + C2H5OH = 4 COOC2H5 + 3 H2O
Na2S + Cu(NO3)2 = NaNO3 + CuS =>
Na2S + Cu(NO3)2 = 2 NaNO3 + CuS
Sn + Ag2CrO4 = Sn(CrO4)4 + Ag =>
Sn + 4 Ag2CrO4 = Sn(CrO4)4 + 8 Ag
C6H5CH3 + HNO3 = C6H2CH3(NO2)3 + H2O =>
C6H5CH3 + 3 HNO3 = C6H2CH3(NO2)3 + 3 H2O
C16H34 = C2H4 + C8H18 =>
C16H34 = 4 C2H4 + C8H18
Al(OH)2F + Ba(OH)2 = Al(OH)2 + Ba(OH)2F =>
Al(OH)2F + Ba(OH)2 = Al(OH)2 + Ba(OH)2F
Pb + HNO3 = Pb(NO3)2 + NO + H2O =>
3 Pb + 8 HNO3 = 3 Pb(NO3)2 + 2 NO + 4 H2O
UO2(NO3)2 + KOH = K2O7U2 + KNO3 + H2O =>
2 UO2(NO3)2 + 6 KOH = K2O7U2 + 4 KNO3 + 3 H2O
SF4 + I2O5 = IF5 + SO2 =>
5 SF4 + 2 I2O5 = 4 IF5 + 5 SO2
N2 + O2 = N2O5 =>
2 N2 + 5 O2 = 2 N2O5
Zn + Ba(OH)2 = Ba + Zn(OH)2 =>
Zn + Ba(OH)2 = Ba + Zn(OH)2
BaSO3 + HBr = BaBr2 + H2SO3 =>
BaSO3 + 2 HBr = BaBr2 + H2SO3
CrCl3 + NaNo3 + NaOH = Na2CrO4 + NaNo2 + NaCl + H2O =>
CrCl3 + 6 NaNo3 + 8 NaOH = Na2CrO4 + 9 NaNo2 + 3 NaCl + 4 H2O
NaCI + Ba(OH)2 = Na(OH)2 + BaCI =>
NaCI + Ba(OH)2 = Na(OH)2 + BaCI
Cl2 + NaOH = NaCl + NaClO + H2O =>
Cl2 + 2 NaOH = NaCl + NaClO + H2O
Na2C2O4 + H2SO4 + KMnO4 = MnSO4 + K2SO4 + Na2SO4 + H2O + CO2 =>
5 Na2C2O4 + 8 H2SO4 + 2 KMnO4 = 2 MnSO4 + K2SO4 + 5 Na2SO4 + 8 H2O + 10 CO2
AgNO3 + Na2SO4 = Ag2SO4 + NaNO3 =>
2 AgNO3 + Na2SO4 = Ag2SO4 + 2 NaNO3
Pb + HNO3 = Pb(NO3)2 + NO + H2O =>
3 Pb + 8 HNO3 = 3 Pb(NO3)2 + 2 NO + 4 H2O
Na2SO4 + Ca(NO3)2 = CaSO4(s) + NaNO3 =>
Na2SO4 + Ca(NO3)2 = CaSO4(s) + 2 NaNO3
(NH4)2Fe(SO4)2 + CaCO3 = (NH4)2Fe(CO3)2 + CaSO4 =>
(NH4)2Fe(SO4)2 + 2 CaCO3 = (NH4)2Fe(CO3)2 + 2 CaSO4
CoCl2 + Na2CO3 = CoCO3 + NaCl =>
CoCl2 + Na2CO3 = CoCO3 + 2 NaCl
Na2(Sn(OH)4) + H2SO4 = Na2SO4 + SnSO4 + H2O =>
Na2(Sn(OH)4) + 2 H2SO4 = Na2SO4 + SnSO4 + 4 H2O
Ca(OH)2 + H6C2O6 = CaC2O4 + H2O =>
Ca(OH)2 + H6C2O6 = CaC2O4 + 4 H2O
Cs2SO4(s) + BaBr2(s) = CsBr(s) + BaSO4(s) =>
Cs2SO4(s) + BaBr2(s) = 2 CsBr(s) + BaSO4(s)
MgCl + KCO3 = MgCO3 + KCl =>
MgCl + KCO3 = MgCO3 + KCl
Al + H2O = H{+} + H2 + Al(OH)4{-}1 =>
2 Al + 8 H2O = 2 H{+} + 3 H2 + 2 Al(OH)4{-}1
fluorine + calcium = CaF =>
F2 + 2 Ca = 2 CaF
Cr2O72 + NO2 = NO3 + Cr =>
Cr2O72 + 72 NO2 = 72 NO3 + 2 Cr
Al2O3 + P2O5 = Al(PO4) =>
Al2O3 + P2O5 = 2 Al(PO4)
H2O + CO2 = C3H12O6 + O2 =>
6 H2O + 3 CO2 = C3H12O6 + 3 O2
CHCl3 + NH3 + NaOH = NaCN + NaCl + H2O =>
CHCl3 + NH3 + 4 NaOH = NaCN + 3 NaCl + 4 H2O
CuCl2 + Fe = Cu + FeCl3 =>
3 CuCl2 + 2 Fe = 3 Cu + 2 FeCl3
Ca3Co2O6 = Ca + Co + O =>
Ca3Co2O6 = 3 Ca + 2 Co + 6 O
K2CO3 + TiO2 + CaF2 + H2SO4 = K2TiF6 + CaSO4 + H2O + CO2 =>
K2CO3 + TiO2 + 3 CaF2 + 3 H2SO4 = K2TiF6 + 3 CaSO4 + 3 H2O + CO2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 12/20/23
Equations balanced on 01/19/23
Lascia un commento sulla tua esperienza con bilanciatore di equazioni chimiche.