Equations balanced on the previous day | Equations balanced on the next day |
3 CrF2 + Al2(CO3)3 = 2 AlF3 + 3 Cr(CO3)
H3PO4 + NaOH = NaH3P2O7 + H2O =>
2 H3PO4 + NaOH = NaH3P2O7 + 2 H2O
TiCl4(s) + H2O(l) = TiO2(s) + HCl(q) =>
TiCl4(s) + 2 H2O(l) = TiO2(s) + 4 HCl(q)
Cl + VI5 = ClI + V =>
5 Cl + VI5 = 5 ClI + V
NaC2H3O2 = Na + C + H + O =>
NaC2H3O2 = Na + 2 C + 3 H + 2 O
FeO + HBr = FeBr + OH =>
FeO + HBr = FeBr + OH
Na + Ca{2+} = Na{+2} + Ca =>
Na + Ca{2+} = Na{+2} + Ca
Zn(NO3)2 + Na2S = NaNO3 + ZnS =>
Zn(NO3)2 + Na2S = 2 NaNO3 + ZnS
NaOH(aq) + CH3COOH(aq) = H2O(l) + CH3COONa(aq) =>
NaOH(aq) + CH3COOH(aq) = H2O(l) + CH3COONa(aq)
NaFe3(SO4)2(OH)6 + HCl = Fe{3+} + Na{+} + SO4{2-} + H2O + Cl{-} =>
NaFe3(SO4)2(OH)6 + 6 HCl = 3 Fe{3+} + Na{+} + 2 SO4{2-} + 6 H2O + 6 Cl{-}
Fe(NO3)3 + KOH = K(NO3)3 + Fe(OH) =>
Fe(NO3)3 + KOH = K(NO3)3 + Fe(OH)
PdO + CO = Pd + CO2 =>
PdO + CO = Pd + CO2
KIO3 + I2 + HCl = KICl4 + H2O + HICl4 =>
3 KIO3 + I2 + 20 HCl = 3 KICl4 + 9 H2O + 2 HICl4
C8H18 + O2 = CO2 + H2O =>
2 C8H18 + 25 O2 = 16 CO2 + 18 H2O
CO2(g) + H(g) = CH4(g) + H2O(l) =>
CO2(g) + 8 H(g) = CH4(g) + 2 H2O(l)
SiH(CH2CH3)3 + GaCl3 = [GaHCl2]2 + Si(CH2CH3)3Cl =>
2 SiH(CH2CH3)3 + 2 GaCl3 = [GaHCl2]2 + 2 Si(CH2CH3)3Cl
ClO4{-} + Fe{2+} + H{+} = Cl + Fe{3+} + H2O =>
ClO4{-} + 7 Fe{2+} + 8 H{+} = Cl + 7 Fe{3+} + 4 H2O
Zn(s) + AnswerHCl(aq) = AnswerZnCl2(aq) + AnswerH2(g) =>
Zn(s) + 2 AnswerHCl(aq) = AnswerZnCl2(aq) + AnswerH2(g)
Cr(NO3)3 + NH3 + H2O = Cr(OH)3 + NH3NO3 =>
3 Cr(NO3)3 + 7 NH3 + 6 H2O = 3 Cr(OH)3 + 8 NH3NO3
AlCl3 + H2O = Al(OH)3 + HCl =>
AlCl3 + 3 H2O = Al(OH)3 + 3 HCl
Mn(NO3)2 + KOH + S = K2MnO4 + K2SO4 + NO + H2O =>
3 Mn(NO3)2 + 8 KOH + S = 3 K2MnO4 + K2SO4 + 6 NO + 4 H2O
Cs(s) + H2O(l) = CsOH(aq) + H2(g) =>
2 Cs(s) + 2 H2O(l) = 2 CsOH(aq) + H2(g)
Fe26 + O2 = Fe2O3 =>
2 Fe26 + 39 O2 = 26 Fe2O3
Sm2O3 + MoO3 = Sm2Mo2O9 =>
Sm2O3 + 2 MoO3 = Sm2Mo2O9
CsNO2 + HCl = CsCl + H2 + NO2 =>
2 CsNO2 + 2 HCl = 2 CsCl + H2 + 2 NO2
H2O + NO3{-} + Zn = H{+} + NH3 + ZnO2{-2} =>
5 H2O + NO3{-} + 4 Zn = 7 H{+} + NH3 + 4 ZnO2{-2}
MnSO4 + CaCO3 = MnCO3 + CaSO4 =>
MnSO4 + CaCO3 = MnCO3 + CaSO4
P4 + H2SO4 + H2O = H2S + H3PO4 =>
2 P4 + 5 H2SO4 + 12 H2O = 5 H2S + 8 H3PO4
Na2SO4(aq) + Pb(NO3)2(aq) = PbSO4(s) + NaNO3(aq) =>
Na2SO4(aq) + Pb(NO3)2(aq) = PbSO4(s) + 2 NaNO3(aq)
LiCl + HNO3 + O2 = LiNO3 + Cl2 + H2O =>
4 LiCl + 4 HNO3 + O2 = 4 LiNO3 + 2 Cl2 + 2 H2O
CuCl + ArSO4 = CuSO4 + ArCl =>
CuCl + ArSO4 = CuSO4 + ArCl
O2{-}(aq) + H2O = OH{-}(aq) + O2(g) =>
4 O2{-}(aq) + 2 H2O = 4 OH{-}(aq) + 3 O2(g)
P4O10 + H2O = H3PO4 =>
P4O10 + 6 H2O = 4 H3PO4
Sb + H2O = Sb2O3 + H2 =>
2 Sb + 3 H2O = Sb2O3 + 3 H2
NaClO3 = NaClO + O2 =>
NaClO3 = NaClO + O2
NO + HBrO4 + H2O = Br2 + HNO3 =>
14 NO + 6 HBrO4 + 4 H2O = 3 Br2 + 14 HNO3
SiCl4 + BCl3 + H2 = SiB2 + HCl =>
SiCl4 + 2 BCl3 + 5 H2 = SiB2 + 10 HCl
Ag + PtCl4 = AgCl + Pt =>
4 Ag + PtCl4 = 4 AgCl + Pt
Cl2 + NaBr = NaCl + Br2 =>
Cl2 + 2 NaBr = 2 NaCl + Br2
K[Al(OH)4] + HCl = KCl + H[Al(OH)4] =>
K[Al(OH)4] + HCl = KCl + H[Al(OH)4]
(NH4)3(PO4) + Ba(OH)2 = Ba3(PO4)2 + (NH4)(OH) =>
2(NH4)3(PO4) + 3 Ba(OH)2 = Ba3(PO4)2 + 6(NH4)(OH)
KClO3 = KCl + O2 =>
2 KClO3 = 2 KCl + 3 O2
NaFeO2 + HNO3 = Fe(NO3)3 + NaNO3 + H2O =>
NaFeO2 + 4 HNO3 = Fe(NO3)3 + NaNO3 + 2 H2O
AgOH + NH3 = Ag(NH3)2 + OH =>
AgOH + 2 NH3 = Ag(NH3)2 + OH
NaAlO2 + HCl = NaCl + AlCl3 + Al(OH)3 =>
3 NaAlO2 + 6 HCl = 3 NaCl + AlCl3 + 2 Al(OH)3
Fe(NO3)3 + Na2CO3 = FeCO3 + Na2(NO3)3 =>
Fe(NO3)3 + Na2CO3 = FeCO3 + Na2(NO3)3
CH3CH2CH2CH3OH + H2SO4 + Na2Cr2O7 = CH3COH + Cr2(SO4)3 + Na2SO4 + H2O =>
6 CH3CH2CH2CH3OH + 20 H2SO4 + 5 Na2Cr2O7 = 12 CH3COH + 5 Cr2(SO4)3 + 5 Na2SO4 + 29 H2O
LiCl + HNO3 = LiNO3 + HCl =>
LiCl + HNO3 = LiNO3 + HCl
Cr2O7{2-} + OH{-} = CrO4{2-} + H3O{+} =>
2 Cr2O7{2-} + 3 OH{-} = 4 CrO4{2-} + H3O{+}
CuSO4(aq) + Na2CO3(aq) = CuCO3(s) + Na2SO4 =>
CuSO4(aq) + Na2CO3(aq) = CuCO3(s) + Na2SO4
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 01/18/24
Equations balanced on 02/17/23
Lascia un commento sulla tua esperienza con bilanciatore di equazioni chimiche.