Equations balanced on the previous day | Equations balanced on the next day |
C3H8 + 5 O2 = 3 CO2 + 4 H2O
CoCl26H2O + P(OPh)3 + NaBH4 = CoH[P(OPh)3]4 + BH3 + NaCl + H2O + H2 =>
2 CoCl26H2O + 8 P(OPh)3 + 52 NaBH4 = 2 CoH[P(OPh)3]4 + 52 BH3 + 52 NaCl + 2 H2O + 25 H2
CoCl26H2O + P(OPh)3 + NaBH4 = CoH[P(OPh)3]4 + BH3 + NaCl + H2O + H2 =>
2 CoCl26H2O + 8 P(OPh)3 + 52 NaBH4 = 2 CoH[P(OPh)3]4 + 52 BH3 + 52 NaCl + 2 H2O + 25 H2
HNa + H2O = NaOH + H2 =>
HNa + H2O = NaOH + H2
Pb(NO3)2(aq)MgSO4(aq) = Mg(NO3)2(s)PbSO4(aq) =>
Pb(NO3)2(aq)MgSO4(aq) = Mg(NO3)2(s)PbSO4(aq)
AlCl(OH)2 + NaOH = Al(OH)3 + NaCl =>
AlCl(OH)2 + NaOH = Al(OH)3 + NaCl
(NH4)3PO4 = H3PO4 + NH3 =>
(NH4)3PO4 = H3PO4 + 3 NH3
CaCrO4 + HCl = CaCl2 + H2Cr2O7 + H2O =>
2 CaCrO4 + 4 HCl = 2 CaCl2 + H2Cr2O7 + H2O
NaSO3H2SO4 = NaSO4H2SO3 =>
NaSO3H2SO4 = NaSO4H2SO3
Fe3O + C(s) = Fe(l) + CO2(g) =>
2 Fe3O + C(s) = 6 Fe(l) + CO2(g)
CrO3 + H2 = Cr2O3 + H2O =>
2 CrO3 + 3 H2 = Cr2O3 + 3 H2O
H2 = H3 =>
3 H2 = 2 H3
H3PO4 + Mn(OH)2 = Mn3(PO4)2 + H2O =>
2 H3PO4 + 3 Mn(OH)2 = Mn3(PO4)2 + 6 H2O
CuO + H2SO4 = CuSO4 + H2O =>
CuO + H2SO4 = CuSO4 + H2O
CoCl26H2O + P(OPh)3 + NaBH4 = CoH[P(OPh)3]4 + BH3 + NaCl + H2O + H2 =>
2 CoCl26H2O + 8 P(OPh)3 + 52 NaBH4 = 2 CoH[P(OPh)3]4 + 52 BH3 + 52 NaCl + 2 H2O + 25 H2
CoCl26H2O + P(OPh)3 + NaBH4 = CoH[P(OPh)3]4 + BH3 + NaCl + H2O + H2 =>
2 CoCl26H2O + 8 P(OPh)3 + 52 NaBH4 = 2 CoH[P(OPh)3]4 + 52 BH3 + 52 NaCl + 2 H2O + 25 H2
BrCl + H2O = HCl + HBrO =>
BrCl + H2O = HCl + HBrO
C15H35COOH + O2 = CO + H2O =>
C15H35COOH + 16 O2 = 16 CO + 18 H2O
Li2O + Co2 = Li2Co3 + O2 =>
2 Li2O + 3 Co2 = 2 Li2Co3 + O2
C10H15NO + KClO4 = KCl + CO2 + NO2 + H2O =>
8 C10H15NO + 57 KClO4 = 57 KCl + 80 CO2 + 8 NO2 + 60 H2O
BrCl + H2O = Br + HBrO3 + HCl =>
5 BrCl + 3 H2O = 4 Br + HBrO3 + 5 HCl
MgO + H2 = MgOH =>
2 MgO + H2 = 2 MgOH
NH4OH + O2 = NH3O + OH =>
NH4OH + O2 = NH3O + 2 OH
HI(g) = H(g) + I2(g) =>
2 HI(g) = 2 H(g) + I2(g)
MgO + H2 = MgOH =>
2 MgO + H2 = 2 MgOH
CoCl26H2O + P(OPh)3 + NaBH4 = CoH[P(OPh)3]4 + BH3 + NaCl + H2O + H2 =>
2 CoCl26H2O + 8 P(OPh)3 + 52 NaBH4 = 2 CoH[P(OPh)3]4 + 52 BH3 + 52 NaCl + 2 H2O + 25 H2
FeCr04 + NaCO3 + O2 = Na2CrO4 + Fe2O3 + CO2 =>
4 FeCr04 + 32 NaCO3 + 19 O2 = 16 Na2CrO4 + 2 Fe2O3 + 32 CO2
Al2O3 + HCe = AlCe3 + H2O =>
Al2O3 + 6 HCe = 2 AlCe3 + 3 H2O
HgOH + H2TeO3 = Hg2TeO3 + H2O =>
2 HgOH + H2TeO3 = Hg2TeO3 + 2 H2O
CaCl2 + LiBr = LiCl2 + CaBr =>
CaCl2 + LiBr = LiCl2 + CaBr
Ca(MnO2)4 + KNO2 + H2SO4 = MnSO4 + KNO3 + CaSO4 + H2O =>
Ca(MnO2)4 + 3 KNO2 + 5 H2SO4 = 4 MnSO4 + 3 KNO3 + CaSO4 + 5 H2O
Li2O + CO2 = LiO2 + C =>
2 Li2O + 3 CO2 = 4 LiO2 + 3 C
Al + H2SO4 = Al2(SO4)3 + H2 =>
2 Al + 3 H2SO4 = Al2(SO4)3 + 3 H2
BrCl + H2O = Br2 + HBrO3 + HCl =>
5 BrCl + 3 H2O = 2 Br2 + HBrO3 + 5 HCl
AuCl + Na2SO3 + H2O = Au + Na2SO4 + HCl =>
2 AuCl + Na2SO3 + H2O = 2 Au + Na2SO4 + 2 HCl
Li2O + CO2 = LiO2 + C =>
2 Li2O + 3 CO2 = 4 LiO2 + 3 C
CaCl2 + LiBr = LiCl2 + CaBr =>
CaCl2 + LiBr = LiCl2 + CaBr
Cr2O7{2-}(aq) + Cl2(g) + H{+}(aq) = Cr{3+}(aq) + ClO3{-}(aq) + H2O(l) =>
5 Cr2O7{2-}(aq) + 3 Cl2(g) + 34 H{+}(aq) = 10 Cr{3+}(aq) + 6 ClO3{-}(aq) + 17 H2O(l)
Li2O + CO2 = LiO2 + C =>
2 Li2O + 3 CO2 = 4 LiO2 + 3 C
CoCl26H2O + P(OPh)3 + NaBH4 = CoH[P(OPh)3]4 + BH3 + NaCl + H2O + H2 =>
2 CoCl26H2O + 8 P(OPh)3 + 52 NaBH4 = 2 CoH[P(OPh)3]4 + 52 BH3 + 52 NaCl + 2 H2O + 25 H2
MnO + Mg = Mn + MgO =>
MnO + Mg = Mn + MgO
LiOH + CO2 = Li2CO3 + H2O =>
2 LiOH + CO2 = Li2CO3 + H2O
BrCl + H2O = Br2 + HBrO3 + HCl =>
5 BrCl + 3 H2O = 2 Br2 + HBrO3 + 5 HCl
MoO3 + H = MoO2 + H2O =>
MoO3 + 2 H = MoO2 + H2O
CaCl2 + LiBr = LiCl2 + CaBr =>
CaCl2 + LiBr = LiCl2 + CaBr
MnO2 + H2SO4 = Mn2SO4 + H2O + O2 =>
4 MnO2 + 2 H2SO4 = 2 Mn2SO4 + 2 H2O + 3 O2
CaCl2 + LiBr = LiCl2 + CaBr =>
CaCl2 + LiBr = LiCl2 + CaBr
HgS + Cl{-} = HgCl4{2-} + S + e =>
HgS + 4 Cl{-} = HgCl4{2-} + S + 2e
Li2O + CO2 = LiO2 + C =>
2 Li2O + 3 CO2 = 4 LiO2 + 3 C
BrCl + H2O = Br2 + HBrO3 + HCl =>
5 BrCl + 3 H2O = 2 Br2 + HBrO3 + 5 HCl
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/22/24
Equations balanced on 03/23/23
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