Equations balanced on the previous day | Equations balanced on the next day |
Zn + 2 HCl = ZnCl2 + H2
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4 =>
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4 =>
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4
BaCrO4 + CH3COOH = (CH3COO)2Ba + H2CrO4 =>
BaCrO4 + 2 CH3COOH = (CH3COO)2Ba + H2CrO4
CH3COOH + NH4Cl = NH4CH3COO + HCl =>
CH3COOH + NH4Cl = NH4CH3COO + HCl
CH3COOH + NH4Cl = NH4CH3COO + HCl =>
CH3COOH + NH4Cl = NH4CH3COO + HCl
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4 =>
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4
BaCrO4 + CH3COOH = (CH3COO)2Ba + H2CrO4 =>
BaCrO4 + 2 CH3COOH = (CH3COO)2Ba + H2CrO4
CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4 =>
2 CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4
CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4 =>
2 CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4
CH3COOH + NH4Cl = NH4CH3COO + HCl =>
CH3COOH + NH4Cl = NH4CH3COO + HCl
BaCrO4 + CH3COOH = (CH3COO)2Ba + H2CrO4 =>
BaCrO4 + 2 CH3COOH = (CH3COO)2Ba + H2CrO4
CH3COOH + NH4Cl = NH4CH3COO + HCl =>
CH3COOH + NH4Cl = NH4CH3COO + HCl
CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4 =>
2 CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4 =>
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4
BaCrO4 + CH3COOH = (CH3COO)2Ba + H2CrO4 =>
BaCrO4 + 2 CH3COOH = (CH3COO)2Ba + H2CrO4
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4 =>
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4 =>
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4
CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4 =>
2 CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4
CH3COOH + NH4Cl = NH4CH3COO + HCl =>
CH3COOH + NH4Cl = NH4CH3COO + HCl
FeCl2 = Cl2Fe =>
FeCl2 = Cl2Fe
CH3COOH + NH4Cl = NH4CH3COO + HCl =>
CH3COOH + NH4Cl = NH4CH3COO + HCl
BaCrO4 + CH3COOH = (CH3COO)2Ba + H2CrO4 =>
BaCrO4 + 2 CH3COOH = (CH3COO)2Ba + H2CrO4
BaCrO4 + CH3COOH = (CH3COO)2Ba + H2CrO4 =>
BaCrO4 + 2 CH3COOH = (CH3COO)2Ba + H2CrO4
BaCrO4 + CH3COOH = (CH3COO)2Ba + H2CrO4 =>
BaCrO4 + 2 CH3COOH = (CH3COO)2Ba + H2CrO4
CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4 =>
2 CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4 =>
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4
CH3COOH + NH4Cl = NH4CH3COO + HCl =>
CH3COOH + NH4Cl = NH4CH3COO + HCl
CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4 =>
2 CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4
CH3COOH + NH4Cl = NH4CH3COO + HCl =>
CH3COOH + NH4Cl = NH4CH3COO + HCl
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4 =>
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4
Fe + O2 = Fe2O3 =>
4 Fe + 3 O2 = 2 Fe2O3
Mg(s) + NiCl2(aq) = Ni(s) + MgCl2(aq) =>
Mg(s) + NiCl2(aq) = Ni(s) + MgCl2(aq)
C2H5OC2H3 + O2 = CO2 + H2O =>
2 C2H5OC2H3 + 11 O2 = 8 CO2 + 8 H2O
C2H2 + O2 = CO2 + H2O =>
2 C2H2 + 5 O2 = 4 CO2 + 2 H2O
BaCrO4 + CH3COOH = (CH3COO)2Ba + H2CrO4 =>
BaCrO4 + 2 CH3COOH = (CH3COO)2Ba + H2CrO4
CH3COOH + NH4Cl = NH4CH3COO + HCl =>
CH3COOH + NH4Cl = NH4CH3COO + HCl
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4 =>
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4
BaCrO4 + CH3COOH = (CH3COO)2Ba + H2CrO4 =>
BaCrO4 + 2 CH3COOH = (CH3COO)2Ba + H2CrO4
BaCrO4 + CH3COOH = (CH3COO)2Ba + H2CrO4 =>
BaCrO4 + 2 CH3COOH = (CH3COO)2Ba + H2CrO4
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4 =>
CH3COOH + BaCrO4 = CH3COO(Ba) + HCrO4
CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4 =>
2 CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4
CH3COOH + NH4Cl = NH4CH3COO + HCl =>
CH3COOH + NH4Cl = NH4CH3COO + HCl
CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4 =>
2 CH3COOH + BaCrO4 = Ba(CH3COO)2 + H2CrO4
SnCl4 + NH4OH + HCl = (NH4)2[SnCl6] + H2O =>
SnCl4 + 2 NH4OH + 2 HCl = (NH4)2[SnCl6] + 2 H2O
HCl + KI = KCl + I2 + H2 =>
2 HCl + 2 KI = 2 KCl + I2 + H2
NaCl + H2O = HOCl + NaOH + H2 =>
NaCl + 2 H2O = HOCl + NaOH + H2
Ag2CO3 + Sn3 + N2 = Ag3N + Sn2(CO3)4 =>
12 Ag2CO3 + 2 Sn3 + 4 N2 = 8 Ag3N + 3 Sn2(CO3)4
HCOOH + Fe(OH)3 = Fe(HCOO)3 + H2O =>
3 HCOOH + Fe(OH)3 = Fe(HCOO)3 + 3 H2O
HCOOH + Fe(OH)3 = Fe(HCOO)3 + H2O =>
3 HCOOH + Fe(OH)3 = Fe(HCOO)3 + 3 H2O
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 05/06/24
Equations balanced on 06/05/23
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