Equations balanced on the previous day | Equations balanced on the next day |
2 NaCl + FeO = Na2O + FeCl2
NaOH + HOCl = NaCl + OH =>
NaOH + HOCl = NaCl + 2 OH
Au(s) + NaCN(aq) + O2(g) + H2O = Na[Au(CN)2](aq) + NaOH(aq) =>
4 Au(s) + 8 NaCN(aq) + O2(g) + 2 H2O = 4 Na[Au(CN)2](aq) + 4 NaOH(aq)
VCl4 + KMnO4 = KCl + MnCl2 + V2O5 + Cl2 =>
16 VCl4 + 10 KMnO4 = 10 KCl + 10 MnCl2 + 8 V2O5 + 17 Cl2
MgCl2 = Mg + Cl2 =>
MgCl2 = Mg + Cl2
As2O3 + MnO4{-} + H2O = AsO4{3-} + Mn{2+} + H3O{+} =>
5 As2O3 + 4 MnO4{-} + 27 H2O = 10 AsO4{3-} + 4 Mn{2+} + 18 H3O{+}
Cr2O7{2-} + H2O2 + H{+} = H2CrO5 + H2O =>
Cr2O7{2-} + 2 H2O2 + 2 H{+} = 2 H2CrO5 + H2O
HNO3 + Al(OH)3 = Al(NO3)3 + H2O =>
3 HNO3 + Al(OH)3 = Al(NO3)3 + 3 H2O
Cl2O + Ca(OH)2 = Cl2O2Ca + H2O =>
Cl2O + Ca(OH)2 = Cl2O2Ca + H2O
C6H6O4 + HCl = C6H8O4Cl2 =>
C6H6O4 + 2 HCl = C6H8O4Cl2
KMnO4 + HCl = KCl + MnCl2 + H2O + Cl2 =>
2 KMnO4 + 16 HCl = 2 KCl + 2 MnCl2 + 8 H2O + 5 Cl2
CaF2 + Ag2S = CaS + AgF =>
CaF2 + Ag2S = CaS + 2 AgF
Au(s) + NaCN(aq) + O2(g) + H2O = Na[Au(CN)2](aq) + NaOH(aq) =>
4 Au(s) + 8 NaCN(aq) + O2(g) + 2 H2O = 4 Na[Au(CN)2](aq) + 4 NaOH(aq)
As2O3 + MnO4{-} + H2O = AsO4{3-} + Mn{2+} + H3O{+} =>
5 As2O3 + 4 MnO4{-} + 27 H2O = 10 AsO4{3-} + 4 Mn{2+} + 18 H3O{+}
C6H6O4 + HCl = C6H8O4Cl2 =>
C6H6O4 + 2 HCl = C6H8O4Cl2
Fe{3+} + K4[Fe(CN)6] = Fe4[Fe(CN)6]3 + K{+} =>
4 Fe{3+} + 3 K4[Fe(CN)6] = Fe4[Fe(CN)6]3 + 12 K{+}
HNO3 + C(OH)2 = C(NO3)2 + H2O =>
2 HNO3 + C(OH)2 = C(NO3)2 + 2 H2O
Al(s) + ZnCl2(aq) = AlCl2 + Zn =>
Al(s) + ZnCl2(aq) = AlCl2 + Zn
C6H6O4 + HCl = C6H8O4Cl2 =>
C6H6O4 + 2 HCl = C6H8O4Cl2
Co(OH)2 = Co + OH =>
Co(OH)2 = Co + 2 OH
H2SO4 + NaOH = Na2SO4 + H2O =>
H2SO4 + 2 NaOH = Na2SO4 + 2 H2O
Li2O4 + HCl = LiCl4 + H2O =>
Li2O4 + 8 HCl = 2 LiCl4 + 4 H2O
As2O3 + MnO4{-} + H2O = AsO4{3-} + Mn{2+} + H3O{+} =>
5 As2O3 + 4 MnO4{-} + 27 H2O = 10 AsO4{3-} + 4 Mn{2+} + 18 H3O{+}
As2O3 + MnO4{-} + H2O = AsO4{3-} + Mn{2+} + H3O{+} =>
5 As2O3 + 4 MnO4{-} + 27 H2O = 10 AsO4{3-} + 4 Mn{2+} + 18 H3O{+}
Li + AlCl3 = LiCl3 + Al =>
Li + AlCl3 = LiCl3 + Al
As2O3 + MnO4{-} + H2O = AsO4{3-} + Mn{2+} + H3O{+} =>
5 As2O3 + 4 MnO4{-} + 27 H2O = 10 AsO4{3-} + 4 Mn{2+} + 18 H3O{+}
Au(s) + NaCN(aq) + O2(g) + H2O = Na[Au(CN)2](aq) + NaOH(aq) =>
4 Au(s) + 8 NaCN(aq) + O2(g) + 2 H2O = 4 Na[Au(CN)2](aq) + 4 NaOH(aq)
CH4 + O2 = CO2 + H2O =>
CH4 + 2 O2 = CO2 + 2 H2O
Cr2O7{2-} + H2O2 + H{+} = H2CrO5 + H2O =>
Cr2O7{2-} + 2 H2O2 + 2 H{+} = 2 H2CrO5 + H2O
K2S + HNO3 = KNO3 + H2S =>
K2S + 2 HNO3 = 2 KNO3 + H2S
C2H6 + O2 = CO2 + H2O =>
2 C2H6 + 7 O2 = 4 CO2 + 6 H2O
H3BO3 + NaOH = H2O + Na2B4O7 =>
4 H3BO3 + 2 NaOH = 7 H2O + Na2B4O7
S8 + Na2SO3 + H2O = Na2S2O3H2O =>
S8 + 8 Na2SO3 + 8 H2O = 8 Na2S2O3H2O
Ba + Cl = BaCl2 =>
Ba + 2 Cl = BaCl2
Sb2S5 + KOH + H2O2 = HSbS2 + H2O + K2SO4 =>
Sb2S5 + 2 KOH + 2 H2O2 = 2 HSbS2 + 2 H2O + K2SO4
Zn + AgNO3 = Zn(NO3)2 + Ag =>
Zn + 2 AgNO3 = Zn(NO3)2 + 2 Ag
NH3 + H2C2O4 = N2C2O4 + H2 =>
2 NH3 + H2C2O4 = N2C2O4 + 4 H2
NaCl + F2 = NaF + Cl2 =>
2 NaCl + F2 = 2 NaF + Cl2
FeSO4 + NH4OH = H2SO4 + Fe(OH)2 + NH3 =>
FeSO4 + 2 NH4OH = H2SO4 + Fe(OH)2 + 2 NH3
Fe2S3 + HCl = FeCl3 + H2S =>
Fe2S3 + 6 HCl = 2 FeCl3 + 3 H2S
FeCl3 + (NH4)2S = Fe2S3 + NH4Cl =>
2 FeCl3 + 3(NH4)2S = Fe2S3 + 6 NH4Cl
Cr2O7{2-} + H2O2 + H{+} = CrO5 + H2O =>
Cr2O7{2-} + 4 H2O2 + 2 H{+} = 2 CrO5 + 5 H2O
HCl + Fe(OH)3 = H2O + FeCl3 =>
3 HCl + Fe(OH)3 = 3 H2O + FeCl3
NaOH0 + H2SO4 = Na2SO4 + H2O =>
2 NaOH0 + H2SO4 = Na2SO4 + 2 H2O
Cr2O7{2-} + H2O2 + H{+} = H2CrO5 + H2O =>
Cr2O7{2-} + 2 H2O2 + 2 H{+} = 2 H2CrO5 + H2O
Cr2O7{2-} + H2O2 + H{+} = H2CrO5 + H2O =>
Cr2O7{2-} + 2 H2O2 + 2 H{+} = 2 H2CrO5 + H2O
Li3N + NH4NO3 = LiNO3 + (NH4)3N =>
Li3N + 3 NH4NO3 = 3 LiNO3 + (NH4)3N
H2SO4 + KOH = K2SO4 + H2O =>
H2SO4 + 2 KOH = K2SO4 + 2 H2O
CH4 + H2O = H2 + CO =>
CH4 + H2O = 3 H2 + CO
C4H9Cl + C3H7OH + C3H6O = C3H7C4H9OCl =>
2 C4H9Cl + C3H7OH + C3H6O = 2 C3H7C4H9OCl
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/20/24
Equations balanced on 03/21/23
Lascia un commento sulla tua esperienza con bilanciatore di equazioni chimiche.