Equations balanced on the previous day | Equations balanced on the next day |
2*Mn(NO3)2 + 2*C2H5NO2 = Mn2O3 + 3 N2 + 4 CO2 + 5 H2O
Pb(CH3COOH)4 + Na(CN) = Pb(CN) + Na(CH3COOH)4 =>
Pb(CH3COOH)4 + Na(CN) = Pb(CN) + Na(CH3COOH)4
Be2C + H2O = Be(OH)2 + CH4 =>
Be2C + 4 H2O = 2 Be(OH)2 + CH4
*Mn(NO3)2 + *C2H5NO2 = Mn2O3 + N2 + CO2 + H2O =>
2*Mn(NO3)2 + 2*C2H5NO2 = Mn2O3 + 3 N2 + 4 CO2 + 5 H2O
KHCO3 = K2CO3 + H2O + CO2 =>
2 KHCO3 = K2CO3 + H2O + CO2
AlCl3 = Al + Cl2 =>
2 AlCl3 = 2 Al + 3 Cl2
Pb(CH3COOH)4 + Na(CN) = Pb(CN) + Na(CH3COOH)4 =>
Pb(CH3COOH)4 + Na(CN) = Pb(CN) + Na(CH3COOH)4
CH2CH2OH + KMnO4 + H2SO4 = CH3COH + MnSO4 + H2O + KSO4 =>
4 CH2CH2OH + KMnO4 + 2 H2SO4 = 4 CH3COH + MnSO4 + 4 H2O + KSO4
I2 + Na2S2O3 = NaI + Na2S4O6 =>
I2 + 2 Na2S2O3 = 2 NaI + Na2S4O6
H2O2 = H2O + O2 =>
2 H2O2 = 2 H2O + O2
*Mn(NO3)2 + *C2H5NO2 = Mn2O3 + N2 + CO2 + H2O =>
2*Mn(NO3)2 + 2*C2H5NO2 = Mn2O3 + 3 N2 + 4 CO2 + 5 H2O
CH2CH2OH + KMnO4 + H2SO4 = CH3COH + MnSO4 + H2O + KSO4 =>
4 CH2CH2OH + KMnO4 + 2 H2SO4 = 4 CH3COH + MnSO4 + 4 H2O + KSO4
CH2CH2OH + KMnO4 + H2SO4 = CH3COH + MnSO4 + H2O + KSO4 =>
4 CH2CH2OH + KMnO4 + 2 H2SO4 = 4 CH3COH + MnSO4 + 4 H2O + KSO4
BF3(g) + H2O(l) = HF(l) + H3BO3(aq) =>
BF3(g) + 3 H2O(l) = 3 HF(l) + H3BO3(aq)
Pb(CH3COOH)4 + Na(CN) = Pb(CN) + Na(CH3COOH)4 =>
Pb(CH3COOH)4 + Na(CN) = Pb(CN) + Na(CH3COOH)4
HC2H3O2 + HCO3 = CO2 + H2O = NaC2H3O2 =>
HC2H3O2 + 8 HCO3 = 10 CO2 + 6 H2O
HC2H3O2 + HCO3 = CO2 + H2O = NaC2H3O2 =>
HC2H3O2 + 8 HCO3 = 10 CO2 + 6 H2O
NH4OH + NaOH = NaNO3 + NH3 + H2 =>
2 NH4OH + NaOH = NaNO3 + NH3 + 4 H2
HC2H3O2 + HCO3 = CO2 + H2O = NaC2H3O2 =>
HC2H3O2 + 8 HCO3 = 10 CO2 + 6 H2O
HC2H3O2 + HCO3 = CO2 + H2O = NaC2H3O2 =>
HC2H3O2 + 8 HCO3 = 10 CO2 + 6 H2O
Mg(CH3COO)2 + LiOH = Mg(OH)2 + LiCH3COO =>
Mg(CH3COO)2 + 2 LiOH = Mg(OH)2 + 2 LiCH3COO
BaSO4 = Ba + SO4 =>
BaSO4 = Ba + SO4
CO2 + H2 + O = H2CO3 =>
CO2 + H2 + O = H2CO3
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2 =>
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2
Rb2O + N2O3 = Rb(NO2) =>
Rb2O + N2O3 = 2 Rb(NO2)
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2 =>
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2
C4H6 + H2 = C4H8 =>
C4H6 + H2 = C4H8
CH4 + Br2 = CBr4 + HBr =>
CH4 + 4 Br2 = CBr4 + 4 HBr
Mg(CH3COO)2 + LiOH = Mg(OH)2 + Li(CH3COO) =>
Mg(CH3COO)2 + 2 LiOH = Mg(OH)2 + 2 Li(CH3COO)
CoCl2 + CrCl3 + NaOH = CoCr2O4 + NaCl + H2O =>
CoCl2 + 2 CrCl3 + 8 NaOH = CoCr2O4 + 8 NaCl + 4 H2O
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2 =>
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2
PO7 + FeCl3 = P5Cl + Fe2O3 + O2 =>
60 PO7 + 4 FeCl3 = 12 P5Cl + 2 Fe2O3 + 207 O2
CH2CH2OH + KMnO4 + H2SO4 = CH3COH + MnSO4 + H2O + KSO4 =>
4 CH2CH2OH + KMnO4 + 2 H2SO4 = 4 CH3COH + MnSO4 + 4 H2O + KSO4
Pb(CH3COOH)4 + Na(CN) = Pb(CN) + Na(CH3COOH)4 =>
Pb(CH3COOH)4 + Na(CN) = Pb(CN) + Na(CH3COOH)4
Pb(CH3COOH)4 + Na(CN) = Pb(CN) + Na(CH3COOH)4 =>
Pb(CH3COOH)4 + Na(CN) = Pb(CN) + Na(CH3COOH)4
Rb3As + NaHSO4 = RbHSO4 + Na3As =>
Rb3As + 3 NaHSO4 = 3 RbHSO4 + Na3As
ZnO + HCl = ZnCl2 + H2 + HO2 =>
4 ZnO + 8 HCl = 4 ZnCl2 + 3 H2 + 2 HO2
CH2CH2OH + KMnO4 + H2SO4 = CH3COH + MnSO4 + H2O + KSO4 =>
4 CH2CH2OH + KMnO4 + 2 H2SO4 = 4 CH3COH + MnSO4 + 4 H2O + KSO4
HC2H3O2 + HCO3 = CO2 + H2O = NaC2H3O2 =>
HC2H3O2 + 8 HCO3 = 10 CO2 + 6 H2O
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2 =>
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2
CuCl + Fe{3+} = Cu{2+} + Fe{2+} + Cl{-} =>
CuCl + Fe{3+} = Cu{2+} + Fe{2+} + Cl{-}
C3H8 + O2 = O2H8 + C3 =>
C3H8 + O2 = O2H8 + C3
Hg + HNO3 + HCl = HgCl2 + NO + H2O =>
3 Hg + 2 HNO3 + 6 HCl = 3 HgCl2 + 2 NO + 4 H2O
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2 =>
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2
SO3 + H2O = H2SO4 =>
SO3 + H2O = H2SO4
SO3 + H2O = H2SO4 =>
SO3 + H2O = H2SO4
LiOH + H2CO3 = Li2CO3 + H2O =>
2 LiOH + H2CO3 = Li2CO3 + 2 H2O
HC2H3O2 + HCO3 = CO2 + H2O = NaC2H3O2 =>
HC2H3O2 + 8 HCO3 = 10 CO2 + 6 H2O
LiOH + HBi = LiBi + H2O =>
LiOH + HBi = LiBi + H2O
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2 =>
LiOH + Mg(CH3COO)2 = MgOH + Li(CH3COO)2
Balance equation of any chemical reaction online for free
Equations balanced on the previous day | Equations balanced on the next day |
Equations balanced on 02/20/24
Equations balanced on 03/21/23
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